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CGP EDU Academic Team
Published on: August 14, 2026
An organic compound P exists in two enantiomeric forms, which have specific optical rotation values [ α ] = ± 100°. The optical rotation of a mixture of these two enantiomers is – 50°. Calculate the percentage of that enantiomer which is in lower concentration in the mixture.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
25%
Sol. Enatiomeirc excess = 
= 
× 100 = 50%
% of laevorotatory isomer = 50 + 25%
% of dextrorotatory isomer = 25%
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