The standard reduction potential of the Ag + /Ag electrode at 298 K is 0.799 V. Given that for AgI, K sp = 8.7 × 10 –17 , evaluate the potential of the Ag + /Ag electrode in a saturated solution of AgI. Also calculate the standard reduction potential of the I – /AgI/Ag electrode.
Text Solution
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Sol. K sp of AgI = [Ag + ][I – ] = 8.7 × 10 –17
In a saturated solution of AgI
[Ag + ] = [I–]
So, [Ag + ] = 
= 
= 9.33 × 10 –9 M
By Nernst equation of Ag + + e ⎯→ Ag(s)
E = Eº – 
= 0.799 – 
= 0.325 V
For standard I – /AgI/Ag electrode, [I – ] = 1.0 M
K sp of AgI = [Ag + ][I – ]
8.7 × 10 –17 = [Ag + [1.0]
∴ [Ag + ] = 
= 8.7 × 10–17
∴ Electode potential,
E = Eº – 
= 0.799 – 
= –0.149 V
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