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CGP EDU Academic Team
Published on: August 14, 2026
A chloride of an element (X) forms yellow precipitate with H 2 S in acidic medium. This yellow precipitate is soluble in Conc. HNO 3 due to formation of compound (Y). Compound (Y) gives ammonium molybdate test then find the metal salt (X).
Text Solution
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AsCl 3 (x) + 3H 2 S 
As 2 S 3 ↓ (yellow ) + 6HCl
3As 2 S 3 + 28HNO 3 +4H 2 O → 6H 3 AsO 4 (y) + 18H + 
+ 28 NO
H 3 AsO 4 (y) + 12 NH 4 MoO 4 +21 HNO 3 → (NH 4 ) AsO 4 .12MoO 3 ↓ (yellow )+21 NH 4 NO 3 +12H 2 O
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