When a metal rod M is dipped into an aqueous colourless concentrated solution of compound N the solution turns light blue. Addition of aqueous NaCl to the blue solution gives a white precipitate O. Addition of aqueous NH 3 dissolves O and gives an intense blue solution.
(i) The metal rod M is :
Text Solution
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(i)b (ii)a (iii)c
Sol.
Cu(M) + AgNO 3 (N) (aqueous colourless solution) ⎯→ Resultant solution contains Cu(NO 3 ) 2 (blue solution) and AgNO 3 (colourless solution)
(N)
Note : Here it is considered that complete AgNO 3 is not utilized in the reaction.
AgNO 3 (aq)+ NaCl (aq) ⎯→ AgCl ↓ (white ) (O) + NaNO 3
Solution containing white ppt. of AgCl also contains Cu(NO 3 ) 2 which developed deep blue colouration with aqueous NH 3 solution
AgCl ↓ (white) + 2NH 3 (aq.) ⎯→ [Ag(NH 3 ) 2 ] +
Cu(NO 3 ) 2 (aq.) + 4NH 3 (aq.) ⎯→ [Cu(NH 3 ) 4 ] (NO 3 ) 2 (deep blue solution)
So, Metal rod M is Cu.
The compound N is AgNO 3 and the final solution contains [Ag(NH 3 ) 2 ] + and [Cu(NH 3 ) 4 ] 2+
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