The volume of hydrogen liberated at STP by treating 2.4 g of magnesium with excess of hydrochloric acid is......x 10 -2 L. Given Molar volume of gas is 22.4 L at STP. Molar mass of magnesium is 24 g mol -1
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The reaction between magnesium 
and hydrochloric acid 
is given by:
From the balanced chemical equation, we can see that 1 mole of magnesium 
produces 1 mole of hydrogen gas 
.
Given that the molar mass of magnesium is 
, and you have 
of magnesium, you can calculate the moles of magnesium using the formula:
Since 1 mole of magnesium produces 1 mole of hydrogen gas, the moles of hydrogen gas produced will also be 
.
Now, at Standard Temperature and Pressure (STP), one mole of any gas occupies a volume of 
. Therefore, the volume 
of hydrogen gas at STP is:
So, the volume of hydrogen gas liberated at STP is 
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