Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The volume of HC1, containing 73 g L -1 required to completely neutralise NaOH obtained by reacting 0.69 g of metallic sodium with water, is _______mL. (Nearest Integer)(Given : molar Masses of Na ? Cl, O, H are 23, 35.5. 16 and 1 e mol -1 respectively)
Text Solution
Verified by ExpertsThe correct answer is:
15
(15)
Mole of Na= 
= 3x10 -2
Na + H 2 O 
NaOH + 
H 2
By using POAC
Moles of NaOH = 3 x 10 -2
NaOH reacts with HC1
No. of equivalent of NaOH = No. of equivalent of HC1
3x10 -2 x1 = 
xV (in L)x 1
V=1.5 x 10 -2 L
Volume of HC1 = 15 ml
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