The maximum oxidation state shown by V(Z = 23), Cr(Z = 24),…

Chemistry D and F - Block Elements General Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: August 13, 2026

The maximum oxidation state shown by V(Z = 23), Cr(Z = 24), Co(Z = 27), Sc(Z = 21) are respectively :

+5, +6, +3, +3

+3, +4, +5, +2

+5, +3, +2, +1

+4 in each case The

Text Solution

Verified by Experts

The correct answer is:

Electron configuration of V is [Ar] 3d 3 4s 2 and thus maximum 5 electrons participate in bonding.

Electron configuration of Cr is [Ar] 3d 5 4s 1 and thus maximum 6 electrons participate in bonding.

Electron configuration of Co is [Ar] 3d 7 4s 2 . In octahedral splitting in presence of ligands, half filled has higher CFSE and thus +3 oxidation state is most stable.

Electron configuration of Sc is [Ar] 3d 1 4s 2 and thus maximum 3 electrons participate in bonding

Previous Question Next Question

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Share this question

Text Solution

Prepare Smarter with CGP Edu

Write a Review

Commentary

Student Reviews

Similar Questions