In the following three tables, information regarding Qualitative analysis of anion is given | |||||
Column-1 | Column-2 | Column-3 | |||
(I) | SO32– | (i) | Reaction with AgNO3 | (P) | Precipitate is obtained |
(II) | Cl– | (ii) | Pungent smelling product with conc. H2SO4 | (Q) | Product is coloured gas. |
(III) | NO2– | (iii) | Form X2 with K2Cr2O7(s) + conc. H2SO4 | (R) | Product formed is soluble in excess NH3. |
(IV) | Br– | (iv) | Reaction with Pb(NO3)2(aq) | (S) | Product gives blue colour with starch iodide solution. |
(i) Select the only correct option.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(i)
SO 3 2– + 2Ag + → Ag 2 SO 3 ↓
Cl – + conc. H 2 SO 4 → HCl (Colourless pungent smell gas)
SO 3 2– + conc. H 2 SO 4 → SO 2
SO 2 gives blue colour with KIO 3 + starch.
Cl – + K 2 Cr 2 O 7 (s) + conc. H 2 SO 4 → CrO 2 Cl 2 (Chromyl chloride)
Deep red vapour
(ii) NO 2 – + AgNO 3 → AgNO 2 ↓ (White crystalline ppt)
SO 3 2– + conc. H 2 SO 4 → SO 2 (Colourless gas)
Br – + Ag + → AgBr ↓ (yellow ppt)
Soluble in excess NH 3
Br – + conc. H 2 SO 4 → Br 2 (Reddish brown)
(iii) NO 2 – + conc. H 2 SO 4 → NO 2 (Reddish brown)
Br – + conc. H 2 SO 4 → Br 2
Br 2 give blue colour with (KI + starch)
Cl – + Pb(NO 3 ) 2 → PbCl 2 ↓ (White ppt)
Cl – + conc. H 2 SO 4 → HCl
HCl does not give blue colour with starch iodide solution.
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