Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Sulphuric acid reacts with sodium hydroxide as follows:
When 1 L of 0.1 M sulphuric acid solution is allowed to react with 1 L of 0.1 M sodium hydroxide solution, the amount of sodium sulphate formed is:
Text Solution
Verified by ExpertsThe correct answer is:
B
1 L of 
of 
1 L of 
of NaOH
As, 2 moles of NaOH react with 1 mole of 
mole of NaOH react with 
of
Hence, NaOH is the limiting reagent.
As, 2 moles of NaOH produce 
mole of 
mole of NaOH will produce 
Therefore, mass of 
Moles 
molar mass of 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Light travels with a speed of . The distance travelled by light in 1 Femto sec is:
The molecular formula of a commercial resin used for exchanging ions in water softening is (mol. w…
If molecules are removed from , then the number of moles of left are:
If 1 ml of water contains 20 drops, then the number of molecules in a drop of water is:
If of A (atomic mass 50) contains n atoms, how many atoms are there in of elements B: (at wt. 100)
Diborane can be prepared by the following reaction-
If the reaction has a yield, how many moles …