Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Consider the carbanions:
(i) (ii) (iii) (iv)
Which of the following represents the correct order of stability of above given carbanions?
A
. (i) 
(iv) and (iii) 
(ii)
Both and ,
(iv) and (iii) (ii) Both and ,
B
. (ii) 
(i) Only
(i) Only
C
. (iii) 
(ii) and (i) 
(iv)
and and
(ii) and (i) (iv) and and
D
. (ii) < (iv) Both
Text Solution
Verified by ExpertsThe correct answer is:
D
As we know that compound (iv) is aromatic and the compound (i) is anti-aromatic. Hence compound (iv) is most stable and compound (i) is least stable. Among these in compound (iii) is more stable than (ii) due to its bond angle that provide minimum strain. Therefore, correct order of stability of given carbonions is: (i) 
(iii) 
(ii) 
(i)
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