Published by:
CGP EDU Academic Team
Published on: August 14, 2026
When a liquid that is immiscible with water was steam distilled at 95.2ºC at a total pressure of 748 torr, the distillate contained 1.25 g of the liquid per gram of water. The vapour pressure of water is 648 torr at 95.2ºC, what is the molar mass of liquid?
Text Solution
Verified by ExpertsThe correct answer is:
C
For two immiscible liquid;
Pº A = P total – Pº H2O = 748 – 648 ⇒ 100
=
; M A =
×
⇒ 145.8
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
On adding solute to a solvent having vapour pressure 0.80 atm , vapour pressure reduces to 0.60 atm…
A solution containing 30 gms of non-volatile solute in exactly 90 gm water has a vapour pressure of…
Vapour pressure of a solution of of non- electrolyte in of water at a particular temperature is …
Azeotropic mixture of HCl and water has
The osmotic pressure at of an aqueous solution containing 1.75 g of sucrose per 150 ml solution is
A 1.2 of solution of NaCl is isotonic with 7.2 of solution of glucose. Calculate the van’t Hoff’s f…