Home Chemistry Solution & Colligative Properties General At 40ºC, vapour pressure in Torr of methanol…
Chemistry Solution & Colligative Properties General Single Correct MCQ
Published on: August 14, 2026

At 40ºC, vapour pressure in Torr of methanol and ethanol solution is P = 119x + 135 where x is the mole fraction of methanol. Hence

A
vapour pressure of pure methanol is 119 Torr
B
vapour pressure of pure ethanol is 135 Torr
C
vapour pressure of equimolar mixture of each is 127 Torr
D
mixture is completely immiscible

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Text Solution

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The correct answer is:
B

P = 119 x + 135

x = 1 for pure methanol.

So, Pº methanol = 119 + 135 = 254 Torr

But for pure ethanol x = 0

So, Pº ethanol = 135 Torr

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