Published by:
CGP EDU Academic Team
Published on: August 13, 2026
When 
gas is passed through aqueous HCl solution containing CuCl 2, PbCl 2, BiCl 3,
ZnCl 2 then we do not get a precipitate of
A
CuS
B
PbS
C
D
ZnS
Text Solution
Verified by ExpertsThe correct answer is:
D
Sulphides ppt
Group IV 
Sulphides ppt.
IIA, IIB groups 
IV group K sp
So, group II radicals give ppt. first as compared to IV group.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The ion which is not precipitated by in the presence of HCl is
cannot be used in place of for the precipitation of V group because
Ca and Ba ions are precipitated in fifth group as their
When is passed through an ammoniacal salt solution , a white precipitate is obtained.
Then can b…
In group IV analysis, is added before passing gas because
Disodium hydrogen phosphate is used to test the presence of