Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Consider a Body Centered Cubic(bcc) arrangement, let d e , d fd , d bd be the distances between successive atoms located along the edge, the face-diagonal, the body diagonal respectively in a unit cell. Their order is given by:
Text Solution
Verified by ExpertsThe correct answer is:
C
de = a
d fd = 
d bd = 
∴ d fd > d e > d bd
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