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CGP EDU Academic Team
Published on: August 14, 2026
Sulfide ion in alkaline solution reacts with solid sulfur to form polysulfide ions having formulae S 2 2– , S 3 2– , S 4 2– and so on. S (s) + S 2– (aq) 
S 2 2– (aq) K 1 = 12 & 2S (s) + S 2– (aq) 
S 3 2– (aq) K 2 = 132. What is the equilibrium constant for the formation of S 3 2– from S 2 2– and S?
Text Solution
Verified by ExpertsThe correct answer is:
A
S (s) + S 2– (aq) 
S 2 2– (aq)
K 1 = 12
2S (s) + S 2– (aq) 
S 3 2– (aq)
K 2 = 132
Now (vc), S 2 2– (aq) + S(s) 
S 3 2– (aq)
K eq = 
= 
= 11
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