Published by:
CGP EDU Academic Team
Published on: August 14, 2026
0.1 Mole of CH 3 COOH and 0.05 moles of sodium acetate are mixed and the solution is made up to two liters. On adding 0.01 moles of HCl to this buffer, the change in pH of the buffer is (neglecting dilution effects, K a of acetic acid = 1.8 × 10 –5 ) –
Text Solution
Verified by ExpertsThe correct answer is:
D
pH 1 = pK a + log 
= pK a – log 2
pH 2 = pK a + log 
= pK a – log 
Δ pH = – log 
+ log 2 = log 2 + log 
= 0.30 – 0.4393 = 0.1393 = 0.14
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