Home Chemistry Surface Chemistry JEE ADVANCED Previous Year Question 3 gram of activated charocoal was added to 5…
Chemistry Surface Chemistry JEE ADVANCED Previous Year Question Single Correct MCQ
Published on: August 14, 2026

3 gram of activated charocoal was added to 50 mL of acetic acid solution (0.06N) in a flask. After an hour it was filtered and the strength of the fitrate was found to be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is :

A
18 mg
B
36 mg
C
42 mg
D
54 mg

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Text Solution

Verified by Experts
The correct answer is:
A

Initial m moles of CH 3 COOH = 0.06 × 50

Final m moles of CH 3 COOH = 0.042 × 50

Hence, mass of CH 3 COOH adsorbed per gram of charcoal

= = 18 mg

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