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CGP EDU Academic Team
Published on: August 14, 2026
If Δ H lattice and Δ H hydration of NaCl are respectively 778 and –774.3 kJ mol –1 and Δ S dissolution of NaCl at 298 K is 43 J mol –1 . The value of Δ G° for dissolution of 1 mole of NaCl is -
Text Solution
Verified by ExpertsThe correct answer is:
A
Δ H diss. = Δ H L + Δ H Hyd.
= 778 + (–774. 3) = 3.7 kJ
Δ G diss. = Δ H diss. – T Δ S diss
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