Chemistry Thermodynamics and Thermochemistry IInd & IIIrd Law of Thermodynamics and Entropy ) Single Correct MCQ
Published on: August 13, 2026

Calculate the total entropy change for the transition at 368 K of 1 mol of sulphur from the monoclinic to the rhombic solid state and H = – 401.7 J mol –1 for the transition. Assume the surroundings to be an ice-water. Both at 0 0 C:

A
– 1.09 JK –1
B
1.47 JK –1
C
0.38 JK –1
D
None

Share this question

For Instagram sharing, use “Apps” on mobile or copy the link.

Text Solution

Verified by Experts
The correct answer is:
C

S (system) = = – 1.09 JK –1

The ice-water both absorbs the 401.7 J mol –1 at temperature 273 K

S surrounding = = 1.47 JK –1

and S (universe) = – 1.09 + 1.47 = 0.38 JK –1

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Similar Questions

Explore conceptually related problems

CG
CGP Question Assistant Question Bank + AI Help
Hi! Type your question or upload one screenshot. First I will search related questions from CGP Edu Question Bank. If none match, type YES and I will solve it with AI.
Upload only one screenshot at a time. Flow: Question Bank first → If not matched, type YES for AI solution.