Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Calculate the total entropy change for the transition at 368 K of 1 mol of sulphur from the monoclinic to the rhombic solid state and
H = – 401.7 J mol –1 for the transition. Assume the surroundings to be an ice-water. Both at 0 0 C:
Text Solution
Verified by ExpertsThe correct answer is:
C
S (system) =
= – 1.09 JK –1
The ice-water both absorbs the 401.7 J mol –1 at temperature 273 K
S surrounding =
= 1.47 JK –1
and
S (universe) = – 1.09 + 1.47 = 0.38 JK –1
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
For a reversible spontaneous change is
When disorder of a system increases, the change is said to be
The spontaneous flow of heat is always
Mixing of non-reacting gases is generally accompanied by
An irreversible process occuring isothermally in an isolated system leads to
The entropy values (in JK -1 mol -1 ) of H 2( g ) = 130.6, Cl 2( g ) = 223.0 and HCl ( g ) = 186.7 …