Given below are two statements:
Statement I: Hybridisation, shape and spin only magnetic moment of 
is sp3 
, octahedral and 4.9 BM respectively.
Statement II: Geometry, hybridisation and spin only magnetic moment values (BM) of the ions
and 
respectively are square planar, tetrahedral, octahedral; dsp 2 
and 
.
In the light of the above statements, choose the correct answer from the options given below
Text Solution
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In Statement I, for 
, Cobalt is in +3 oxidation state 
. Carbonate 
is a weak field ligand. Thus, no pairing occurs, resulting in 4 unpaired electrons. Hybridisation is 
, shape is octahedral, and 
. Statement I is true.
In Statement II:
For 
is 
is a strong field ligand, causing pairing. Hybridisation is 
, geometry is square planar, and 
.
For 
is 
is a weak field ligand. Hybridisation is 
, geometry is tetrahedral, and 
.
For 
is 
is a weak field ligand. Hybridisation is 
, geometry is octahedral, and 
.
Statement II is true.
Both statements are true.
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