Given below are two statements:
Statement I: The number of species among 
and 
, that have unequal 
bond lengths is two. Here, E is the central atom.
Statement II: Among 
and 
has the highest bond order.
In the light of the above statements, choose the correct answer from the options given below
Text Solution
Verified by ExpertsA
Statement I: Let's analyze the geometry of the given species.
hybridization, tetrahedral geometry. All B-F bond lengths are equal.
hybridization, tetrahedral geometry. All Si-F bond lengths are equal.
hybridization, square planar geometry. All Xe-F bond lengths are equal.
hybridization, see-saw geometry. It has axial and equatorial bonds. Axial bonds are longer than equatorial bonds due to greater repulsion. Thus, only 
has unequal bond lengths. The number of species is one, not two. Statement I is false.
Statement II: Bond order calculation using Molecular Orbital Theory:
Total electrons in 
, Bond Order 
Total electrons in 
, Bond Order 
Total electrons in 
, Bond Order 
Total electrons in 
, Bond Order 
Among these, 
has the highest bond order (2.5), not 
. Statement II is false.
Both Statement I and Statement II are false.
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