Given below are two statements:
Statement I: Sucrose is dextrorotatory. However, sucrose upon hydrolysis gives a solution having mixture of products. This solution shows laevorotation.
Statement II: Hydrolysis of sucrose gives glucose and fructose. Since the laevorotation of glucose is more than the dextrorotation of fructose, the resulting solution becomes laevorotatory.
In the light of the above statements, choose the correct answer from the options given below
Text Solution
Verified by ExpertsA
Sucrose is dextrorotatory with a specific rotation of 
.
Upon hydrolysis, sucrose breaks down into an equimolar mixture of D-(+)-glucose and D-(-)-fructose.
The specific rotation of D-(+)-glucose is 
(dextrorotatory).
The specific rotation of D-(-)-fructose is 
(laevorotatory).
Since the magnitude of laevorotation of fructose ( 
) is greater than the magnitude of dextrorotation of glucose 
, the resulting mixture is laevorotatory. This process is called inversion of sugar.
Statement I is true because sucrose is dextrorotatory and its hydrolysis product is laevorotatory.
Statement II is false because it incorrectly claims that glucose is laevorotatory and fructose is dextrorotatory, and that the laevorotation of glucose is more than the dextrorotation of fructose. In reality, glucose is dextrorotatory and fructose is laevorotatory.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems