Home Chemistry Alcohol, Phenol and Ether JEE Main 2026 Given below are two statements: Statement I…
Chemistry Alcohol, Phenol and Ether JEE Main 2026 Single Correct MCQ
Published on: August 13, 2026

Given below are two statements:
Statement I: Phenol on treatment with /aq. KOH under refluxing condition, followed by acidification produces -hydroxy benzaldehyde as the major product and -hydroxy benzaldehyde as the minor product.
Statement II: The mixture of -hydroxybenzaldehyde and hydroxybenzaldehyde can be easily separated through steam distillation.

In the light of the above statements, choose the correct answer from the options given below

A
Statement I is true but Statement II is false
B
Statement I is false but Statement II is true
C
Both Statement I and Statement II are true
D
Both Statement I and Statement II are false

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Text Solution

Verified by Experts
The correct answer is:
B

Statement I: The reaction of phenol with and aqueous KOH is the Reimer-Tiemann reaction. In this reaction, the major product is -hydroxybenzaldehyde (salicylaldehyde) due to the formation of a stable sixmembered chelate ring via intramolecular hydrogen bonding. -hydroxybenzaldehyde is formed as the minor product. Thus, Statement I is false.

Statement II: -hydroxybenzaldehyde (salicylaldehyde) has intramolecular hydrogen bonding, making it more volatile (steam volatile). -hydroxybenzaldehyde has intermolecular hydrogen bonding, which leads to association between molecules and a higher boiling point, making it non-steam volatile. Therefore, the mixture can be easily separated by steam distillation. Thus, Statement II is true.

Conclusion: Statement I is false but Statement II is true.

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