Published by:
CGP EDU Academic Team
Published on: August 14, 2026
In the given figure, the electrolytic cell contains 1 L of an aqueous 1 M Copper (II) sulphate solution. If 0.4 mole of electrons are passed through cell, the concentration of copper ion after passage of the charge will be:
Text Solution
Verified by ExpertsThe correct answer is:
C
Number of moles of Cu 2+ produced from anode = number of moles of Cu 2+ deposited at cathode.
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