Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The anodic half–cell of lead–acid battery is recharged using electricity of 0.05 Faraday. The amount of PbSO 4 electrolyzed in g during the process is: (Molar mass of PbSO 4 = 303 g mol –1 )
Text Solution
Verified by ExpertsThe correct answer is:
C

For 2F current passed, PbSO 4 electrolyzed = 303g/mol
For 0.05F; PbSO 4 electrolyzed =
= 7.6g
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Standard electrode potential data are useful for understanding the suitability of an oxidant in a r…
Two students use the same stock solution of ZnSO 4 and different solutions of CuSO 4 to make Daniel…
The emf of the cell, Zn | Zn 2+ (0.01 M) || Fe 2+ (0.001 M) | Fe at 298 K is 0.2905 V. Then the val…
Find the equilibrium constant at 298 K for the reaction :
Cu 2+ (aq) + In 2+ (aq) Cu + (aq) + In 3…
The half cell reactions for rusting of iron are :
2H + + O 2 + 2e – ⎯→ H 2 O; Eº = +1.23 V & Fe 2+…
Redox reactions play a pivoted role in chemistry and biology. The values of standard redox potentia…