Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The molar conductivities 
and 
at infinite dilution in water at 25°C are 91.0 and 426.2 Scm 2 /mol respectively. To calculate 
, the additional value required is :
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
D
CH 3 COONa + HCI → CH 3 COOH + NaCI From the reaction,
+ Λ o HCI = 
+ Λ o NaCI
or 
= 
+ Λ o HCI – Λ o NaCI
Thus to calculate the value of one should know the value of Λ o NaCI along with and Λ o HCI .
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