Chemistry Thermodynamics and Thermochemistry IInd & IIIrd Law of Thermodynamics and Entropy ) Single Correct MCQ
Published on: August 14, 2026

The enthalpy change for a given reaction at 298 K is – x J mol –1 (x being positive). If the reaction occurs spontaneously at 298 K, the entropy change at that temperature

A
Can be negative but numerically larger than x/298
B
Can be negative but numerically smaller than x/298
C
Cannot be negative
D
Cannot be positive

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The correct answer is:
B

It is because of the fact that for spontaneity, the value of G = ( H – T S) should be < 0. If S is – ve, the value of T S shall have to be less than H or the value of S has to be less than i.e., .

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