Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Gaseous N 2 O 5 decomposes according to the following equation :
N 2 O 5 (g) → 2NO 2 (g) + 
O 2 (g)
The experimental rate law is – Δ [N 2 O 5 ]/ Δ t = k[N 2 O 5 ]. At a certain temperature the rate constant is k = 5.0 x 10 –4 /sec. In how seconds will the concentration of N 2 O 5 decrease to one-tenth of its initial value?
Text Solution
Verified by ExpertsThe correct answer is:
B
t = 
log 
= 4.6 ×10 3 sec
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