Arrange the following carbanions in the decreasing order of stability.
(I) 
(II) 
(III) 
(IV) 
(V) 
Choose the correct answer from the options given below:
(IV) 
(II) 
(V) 
(III) 
(II) 
(IV) 
(V) 
(III) 
(I) 
(II) 
(V) 
(III) 
(II) 
(I) 
(III) 
(V)
Text Solution
Verified by ExpertsC
Carbanion stability increases with electron-withdrawing groups (stabilize negative charge) and decreases with electron-donating groups (destabilize negative charge).
(IV) has CHO (strongly electron-withdrawing by inductive effect), most stable.
(I) has Br (weakly electron-withdrawing).
(II) is pure benzyl with resonance from ring.
(V) has 
(weakly electron-donating).
(III) has 
(strongly electron-donating, destabilizes the carbanion).
The critical factor is inductive electron-withdrawing ability:
.
Therefore: IV 
I 
II 
V 
III.
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