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CGP EDU Academic Team
Published on: August 14, 2026
If A.M., G.M. and H.M. of first and last terms of the series 100, 101, 102,…. n –1, n are the terms of the series it self then the value of n is (100 < n ≤ 500 )
Text Solution
Verified by ExpertsThe correct answer is:
C
AM = 
, G.M. = 
, H.M. = 
for AM to be integer, n must be even
for GM to be integer, n must be perfect square
So n = 4k 2 HM = 
= 
= 
for HM to be integer k 2 must be divisible by 25 also 100 < n ≤ 500
k 2 = 50, 75, 100, 125
Hence n = 400 the only which satisfies
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