Published by:
CGP EDU Academic Team
Published on: August 13, 2026
If 'a' is the A.M. of 'b' and 'c' and the two geometric means are G 1 and G 2 , then prove that
= 2abc
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
Sol. 'a' is the A.M. of 'b' and 'c'.
∴ a =
⇒ b + c = 2a ....(i)
b,G 1 ,G 2 ,c are in G.P. with common ratio r = 
∴ G 1 = br =
= c 1/3 b 2/3 and
G 2 = br 2 =
= b 1/3 c 2/3
⇒
= b 2 c and
= bc 2
⇒
= b 2 c + bc 2 ⇒
= bc(b + c)
⇒
= 2abc
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
If a, b, c > 0 then (a + b + c) is -
If the A.M. of the roots of a quadratic equation is 8/5 and the A.M. of their reciprocals is 8/7, t…
The product of n positive numbers is 1, then their sum is a positive integer and is –
If 3 + + + ......... ∞ = 8 then d equals -
If a 2 x 4 + b 2 y 4 = c 6 , then maximum value of xy is :
In an A.P. T n = (3 – 7n) then common difference of A.P. is-