Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Integral part of (7 + 2
) 2n+1 is (n ∈ N)-
Text Solution
Verified by ExpertsThe correct answer is:
A
I + f + F = (7 + 2
) 2n+1 + (7 – 2
) 2n+1
= 2 
= Even integer
F = –k (because F < 0)
So I + f – k = even integer [ f –k ⇒ 0]
So I ⇒ even integer
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