Observe the following list:
Column- I | Column- II |
(i) Number of distinct terms in the expansion of (x + y–z)16 | [A] 212 |
(ii) Number of terms in the expansion of (x + )6 + (x–)6 | [B] 97 |
(iii) The number of irrational terms in | [C] 4 |
(iv) The sum of numerical coefficients in the expansion of | [D] 153 |
Text Solution
Verified by Experts(i) [D]; (ii) [C]; (iii) [B]; (iv) [A]
Ans.
(i) [D]
(ii) [C]
(iii) [B]
(iv) [A]
Sol. (i) (16+3–1) C 3–1 = 18 C 2 = 
= 9 × 17 = 153
(ii) 
+ 1 = 
+ 1 = 3 + 1 = 4
(iii) 
= 4 + F (OCF < 1)
(T 1 , T 25 ,T 49 , T 73 are rationals)
Total number of terms – rational terms = Irrational terms
101 – 4 = 97
(iv) Put x = y = z = 1 ⇒ 
= 2 12
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