Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Let P = (5
+ 8) 2n+1 and f = P –[P], where [.] denotes the greatest integer function. Find Pf.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
Sol. P = (5
+ 8) 2n+1 = [P] + f …(1)
Where 0 ≤ f < 1
Now let (5
–8) 2n+1 = f ′ … (ii)
Where 0 < f ′ < 1
Subtracting (1) and (2), we get
⇒ [P] + f– f ′ = (5
+ 8) 2n+1 – (5
–8) 2n+1 = even integer
⇒ Hence f – f ′ is also an integer.
i.e. f – f ′ = 0 { –1 < f – f ′ < 1}
∴ f = f ′ …(iii)
Now L.H.S. = Pf = Pf ′
from (iii)
= (5
+ 8)
2n+1 (5
–8) 2n+1 = (75 –64)
2n+1 = 11
2n+1 R.H.S.
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