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Maths Quadratic Equations Solution of Quadratic Inequations and Miscellaneous Equations Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: August 13, 2026

Let 6a < 4b < 3c then the equation (2x – a)(3x – b) + (3x – b) (4x – c) + (4x – c)(2x – a) = 0 has

Both roots real

Both roots imaginary

One root lies between

Other root lies between

Text Solution

Verified by Experts

The correct answer is:

CHECK THE SOLUTION.

(a, c, d)

Let f (x) = (2x – a) (3x – b) + (3x – b) (4x – c) + (4x – c) (2x – a) = 0

f = (2a – c) > 0 since

f = < 0

since f f < 0

⇒ one real root between

⇒ Both roots are real

Equation is quadratic in nature.

Also, f > 0

f f < 0 ⇒ other between

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