Maths Permutations & Combination Definition of Permutation, Number of Permutations With or Without Repetition, Conditional Permutations Single Correct MCQ
Published on: August 13, 2026

How many numbers can be made with the help of the digits 0, 1, 2, 3, 4, 5 which are greater than 3000 (repetition is not allowed)

A
180
B
360
C
1380
D
1500

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Text Solution

Verified by Experts
The correct answer is:
C

All the 5 digit numbers and 6 digit numbers are greater than 3000. Therefore number of 5 digit numbers

= .

{Since the case that 0 will be at ten thousand place should be omit}. Similarly number of 6 digit numbers 6 ! – 5 ! = 600.

Now the numbers of 4 digit numbers which are greater than 3000, having 3, 4 or 5 at first place, this can be done in 3 ways and remaining 3 digit may be filled from remaining 5 digits i.e., required number of 4 digit numbers are

.

Hence total required number of numbers = 600 + 600 + 180 = 1380.

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