Published by:
CGP EDU Academic Team
Published on: August 14, 2026
10 different toys are to be distributed among 10 children. Total number of ways of distributing these toys so that exactly 2 children do not get any toy, is equal to -
A
(10!) 2 
B
(10!) 2 
C
(10!) 2 
D
(10!) 2 
Text Solution
Verified by ExpertsThe correct answer is:
B
It is possible in two mutually exclusive cases
Case 1. 2 children get none, one child gets three and all remaining children get one each.
Case 2. Children get none, 2 children get 2 each and all remaining children get one each.
In case one number of ways
= 
· 10!
In second case number of ways
= 
· 10!
Thus total ways
= (10!) 2 
Hence is correct answer.
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