Published by:
CGP EDU Academic Team
Published on: August 12, 2026
In a Δ ABC, if 
= 0 then sin 2 A + sin 2 B + sin 2 C is
equal to -
A
B
C
1
D
3 
Text Solution
Verified by ExpertsThe correct answer is:
A
= 0
⇒ a 2 + b 2 + c 2 – ab – bc – ca = 0
⇒ (a – b) 2 + (b – c) 2 + (c – a) 2 = 0
i.e. a = b = c i.e. A = B = C = 60 0 or sin A = sin B = sin C = 
∴ sin
2 A + sin 2 B + sin 2 C = 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
λ3Δ ABC and Δ DEF have sides of lengths a, b, c and d, e, f respectively (symbols are as per usual …
In a triangle ABC, ∠ A = 60 0 , a = 4 and b = 3, then c is a root of the equation
In a triangle ABC, if cos A + 2cos B + cos C = 2, then a, b, c
are in -
If in triangle ABC, r 1 = 2r 2 = 3r 3 , D is the middle point of BC. Then cos ( ∠ ADC) is equal to -
If in a triangle ABC, sin A, sin B, sin C are in A.P., then -
In triangle ABC, I is the incentre of the triangle. If ‘R’ and ‘r’ be the circumradius and inradius…