Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Solve the equation tan θ + tan 2 θ + tan 3 θ = tan θ tan 2 θ tan 3 θ
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
Sol. tan θ + tan 2 θ + tan 3 θ = tan θ tan 2 θ tan 3 θ
⇒ tan θ + tan 2 θ = – tan 3 θ + tan θ tan 2 θ tan 3 θ
⇒ tan θ + tan 2 θ = – tan 3 θ (1 – tan θ tan 2 θ )
⇒ 
= – tan 3 θ
⇒ tan 3 θ = – tan 3 θ
⇒ 2 tan 3 θ = 0 ⇒ tan 3 θ = 0 ⇒ 3 θ = n π
⇒ θ = n π /3, n ∈ I
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
If 'a' is a real constant and A, B, C are variable anglesand
tan A + a tan B + tan C = 6a then th…
If A + B + C = π , then cos A + cos B – cos C =
A solution of the equation tan –1 (1 + x) + tan –1 (1 – x) = is
2 tan –1 (cos x)= tan –1 (cosec 2 x), then x =
If cot –1 α + cot –1 β = cot –1 x, then x =
If tan –1 x + tan –1 y + tan –1 z = π , then + + =