Published by:
CGP EDU Academic Team
Published on: August 14, 2026
If sin –1 x + sin –1 y + sin –1 z =
and f(1) = 2, f(p +q) = f(p). f(q) ∀ p, q ∈ R, then
–
=
Text Solution
Verified by ExpertsThe correct answer is:
C
–
≤ sin –1 x ≤ 
∴ sin –1 x + sin –1 y + sin – 1 z = 
⇔ sin –1 x = sin –1 y = sin – 1 z = 
⇔ x = y = z = 1
Also f(p + q) = f(p). f(q) ∀ p, q ∈ R …(1)
Given f(1) = 1
from (1),
F(1 + 1) = f(1). F(1) ⇒ f(2) =1 2 = 1
from (2), f(2 + 1) = f(2) . f(1)
⇒ f(3) = 1 2 . 1 = 1 3 = 1
Now given expression = 3 –
= 2
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