Published by:
CGP EDU Academic Team
Published on: August 12, 2026
The inequality sin –1 (sin 5) > x 2 – 4x holds if-
A
x = 2 – 
B
x = 2 + 
C
x ∈ (2 – 
, 2 + 
)
, 2 + )
D
x > 2 + 
Text Solution
Verified by ExpertsThe correct answer is:
C
Since 
,
We have sin 5 < 0, so sin –1 (sin 5) = 2 π – 5
Thus, the given inequality can be written as
2 π – 5 > x 2 – 4x or x 2 – 4x – (2 π – 5) < 0
⇒ 
< 0
⇒ [x – 2 – 
] [x – (2 + 
)] < 0
x ∈ (2 – 
), (2 + 
).
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