Published by:
CGP EDU Academic Team
Published on: August 14, 2026
If A = 2 tan –1 (2 
– 1) and B = 3 sin –1 
+ sin –1 
, then-
Text Solution
Verified by ExpertsThe correct answer is:
C
We have A = 2 tan –1 (2 
– 1) = 2 tan –1 (1.828) ⇒ A > 2 tan –1 
⇒ A > 
Next sin – 1 
< sin –1 
⇒ sin – 1 
< 
⇒ sin – 1 
< 
Also 3 sin – 1 
= sin –1 
= sin –1 
= sin –1 (0. 852)
⇒ 3 sin –1 
< sin –1 
⇒ 3 sin –1 
< 
Further sin –1 
= sin –1 (0. 6) < sin –1 
⇒ sin –1 
< 
Hence, B = 3 sin –1 
+ sin –1 
< 
+ 
= 
. Hence A > B
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