Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The greater of two angles A = 2 tan –1 ( 
–1) and B = 3 sin –1 (1/3) + sin –1 (3/5) is
Text Solution
Verified by ExpertsThe correct answer is:
A
A = 2 tan –1 
= 2 tan –1 (2 × 1.414 –1) = 2 tan –1 (1.828)
⇒ A > 2 tan –1 
= 2 π /3
For angle B, sin –1 
< sin –1 
= 
⇒ 3 sin –1 
< 
3 sin –1 
= sin –1 
= sin –1 
= sin –1 (.851) < sin –1 
= 
⇒ 3 sin –1 
< 
Also sin –1 
= sin –1 (0.6) < sin –1 
= 
so sin –1 
< 
Adding B = 3 sin –1 
+ sin –1 
< 
So A > B
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