Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Given the system of equations px + y + z = 1,
x + py + z = p, x + y + pz = p 2 . Then for what value of p does this system have no solution.
Text Solution
Verified by ExpertsThe correct answer is:
D
Δ = 
= p(p 2 – 1) – 1(p – 1) + 1(1 – p) = 0
= (p – 1) [p(p + 1) – 2] = 0 ⇒ p = 1, –2
at p = 1 gives infinite many solution
at p = –2 at least one of ( Δ 1 , Δ 2 , Δ 3 ) are non zero
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