Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Integers satisfying the inequalit
log 2 2 x + log 2 0.03125x + 3 ≤ 0 is/are–
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION
(c, d)
(log 2 x) 2 + log 2 
+ (log 2 x) + 3 ≤ 0
⇒ (log 2 x) 2 + (log 2 x) – 2 ≤ 0
⇒ (log 2 x + 2) (log 2 x – 1) ≤ 0
⇒ – 2 ≤ log 2 x ≤ 1
⇒ 
≤ x ≤ 2
So integers are x = 1, 2
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