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CGP EDU Academic Team
Published on: August 14, 2026
If a 1 , a 2 , a 3 , …..., a 15 are in A.P. and a 1 + a 8 + a 15 = 15, then a 2 + a 3 + a 8 + a 13 + a 14 is equal to -
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A
a 1 , a 2 , a 3 , …..., a 15 (Odd number of terms in A.P.)
a 1 + a 15 = a 2 + a 14 = …= 2a 8
a 1 + a 15 + a 8 = 
(a 1 + a 15 ) = 15
⇒ a 1 + a 15 = 10
a 2 + a 3 + a 8 + a 13 + a 14 = 2(a 1 + a 15 ) + a 8 = 2(10) + 5 = 25.
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