Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Let A(1, 2), B(3, 4) be two points and C(x, y) be a point such that (x – 1) (x – 3) + (y – 2) (y – 4) = 0. If area of Δ ABC is
1 sq. unit. Then maximum number of positions of C in xy plane is
Text Solution
Verified by ExpertsThe correct answer is:
0004
Ans. 0004
Sol. (x –1) (x – 3) + (y – 2) (y – 4) = 0
Point (x, y) lies on circle with AB as a diameter
Δ ABC = 1sq. unit
× (AB) × (Altitude) = 1
Altitude = 
< radius
So four positions are possible.
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