Published by:
CGP EDU Academic Team
Published on: August 13, 2026
If A(2, 0), B(–2, 0) and C(3, –3) are three points then find the locus of a point P which satisfies the relation :
PA 2 + PB 2 = 2PC 2
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
Sol. Let P(h, k) and A(2, 0), B(–2, 0), C(3, –3)
Given PA 2 + PB 2 = 2PC 2 ⇒ (h – 2)
2 + (k – 0) 2 + (h + 2) 2 + (k – 0) 2 = 2[(h – 3)
2 + (k + 3) 2 ]
⇒ 2h 2 + 2k 2 = 2h 2 + 2k 2 – 12h + 12k + 36
⇒ 12h – 12k – 36 = 0
⇒ h – k – 3 = 0
locus x – y – 3 = 0
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
If the vertices of a triangle are A (1, 4), B (3, 0) and C (2, 1), then the length of the median pa…
The locus of a point represented by
x = , y = is-
The locus of the point of intersection of the lines x + 4y = 2a sin θ , x – y = a cos θ where θ is …
What is the equation of the locus of a point which moves such that 4 times its distance from the x …
The extremities of the diagonal of a parallelogram are the points (3, – 4) and (–6, 5). Third verte…
If the vertices of a triangle are A(1, 4) B(3, 0) and C(2, 1) then the length of the median passing…