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CGP EDU Academic Team
Published on: August 14, 2026
Locus of the centre of the circle touching the angle bisectors between the pair of lines α x 2 + α y 2 + β xy = 0
(where α, β ∈ R) is-
Text Solution
Verified by ExpertsThe correct answer is:
A
α x 2 + α y 2 + β xy = 0 ; equation of bisector 
= 
;
h (x 2 – y 2 ) = (xy) (a –b) ⇒ x 2 – y 2 = 0
Circle touch the lines representing bisector
In all cases one coordinate of centre of circle will be zero.
h × k = 0, x × y = 0.
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