The equation of the radical of a coaxial system of circle w…

Maths Circle and System of Circles Mix Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: August 14, 2026

The equation of the radical of a coaxial system of circle whose limiting points are (2, – 1) and (–3, 2), is -

5x + 3y – 4 = 0

5x + 3y + 4 = 0

5x – 3y + 4 = 0

3x – 5y + 4 = 0

Text Solution

Verified by Experts

The correct answer is:

The equations of circles having (2, –1) and

(–3, 2) as limiting points are

and

Clearly, (1) and (2) are members of the coaxial system of circles whose limiting points are

(2, –1) and (–3, 2).

So, the equation of the radical axis is

⇒ 10x – 6y + 8 = 0

⇒ 5x – 3y + 4 = 0

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